Rezolva inmultirile de mai jos in doua moduri

Rezolva inmultirile de mai jos in doua moduri

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Metoda 1

3 x (2 + 5) = 3 x 7 = 21

(6 - 3) x 4 = 3 x 4 = 12

8 x (4 - 3) = 8 x 1 = 8

(1 + 3) x 6 = 4 x 6 = 24

Metoda 2

3 x (2 + 5) = 3 x 2 + 3 x 5 = 6 + 15 = 21

(6 - 3) x 4 = 6 x 4 - 3 x 4 = 24 - 12 = 12

8 x (4 - 3) = 8 x 4 - 8 x 3 = 32 - 24 = 8

(1 + 3) x 6 = 1 x 6 + 3 x 6 = 6 + 18 = 24

Probleme si exercitii rezolvate clasa a 3-a

Probleme si exercitii rezolvate