Sa se afle
n daca:
C 4n = 5n(n - 3) / 6
=> n! / 4!(n
- 4)! = 5n(n - 3) / 6
=> (n
- 4)! * (n - 3) * (n - 2) * (n - 1) * n / 1 * 2 *
3 * 4 (n - 4)! = 5n(n - 3) / 6
=> (n -
2) * (n - 1) * n / 24 = 5n / 6 (*4)
=> n * (n
- 1) * (n - 2) / 24 = 20n / 24
=> n2 – n + n2 – 2n = 20n
=> 2n2 – 3n = 20n
=> 2n2 – 3n - 20n = 0
=> 2n2 – 23n = 0
=> n(2n - 23) = 0
sol 1=> n = 0
=> 2n - 23 = 0
=> 2n = 23
sol 2=> n = 23 / 2Exercitii rezolvate combinari
Calculator combinari
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Probleme si exercitii rezolvate