A magnifying glass is a convergent lens with small focal length f = 5 cm. An object AB is positioned at x1 = -3 cm to the left of lens. Specify where the image is formed, and what nature has.
Solution
$$x_{2} = \frac{fx_{1}}{f + x_{1}} = - 7,5 \ cm$$
$$β = \frac{x_{2}}{x_{1}} = 1,5$$
It follows that the virtual image obtained is larger than the object with:
$$β = \frac{x_{2}}{x_{1}} = 1,5 \ times$$
Niciun comentariu:
Trimiteți un comentariu