Inmultirea radicalilor clasa a 8-a exercitiu rezolvat 12

$\sqrt{\frac{1}{8}} \cdot \sqrt{\frac{25}{2}}  \ = \ ?$


Rezolvare


Metoda 1 de calcul

$\sqrt{\frac{1}{8}} \cdot \sqrt{\frac{25}{2}} = \sqrt{\frac{1}{4 \cdot 2}} \cdot \sqrt{\frac{5^{2}}{2}} =>$

$\frac{1}{2} \cdot \sqrt{\frac{1}{2}} \cdot 5 \cdot \frac{1}{2} =>$

$\frac{5}{2} \cdot \frac{1}{2} = \boxed{\frac{5}{4}}$



Metoda 2 de calcul

$\sqrt{\frac{1}{8}} \cdot \sqrt{\frac{25}{2}} = \sqrt{\frac{1}{8} \cdot \frac{25}{2}} =>$

$\sqrt{\frac{25}{16}} = \sqrt{\frac{5^{2}}{4^{2}}} => \boxed{\frac{5}{4}}$


Probleme si exercitii rezolvate clasa a 8-a

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